-24y^2-48y/12=0

Solution for -24y^2-48y/12=0 equation:

-24y^2-48y/12=0

We multiply all the terms by the denominator


-24y^2*12-48y=0

Wy multiply elements

-288y^2-48y=0

a = -288; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·(-288)·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*-288}=\frac{0}{-576}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*-288}=\frac{96}{-576}
=-1/6
$